pkufranky

两个goroutine并发执行(Lock, do somthing, UnLock)，使用NewMutex(name), 传入的是相同的name，因此获取的是同一个mutex 假设routine1先成功获取了redis锁，但在UnLock之前，routine2尝试Lock，就可以看到下面的死锁，都在等待localMtx的释放。 似乎单例模式没啥必要？既然名字叫NewMutex，每次返回新的就可以了 routine 1 Lock1 // 执行成功 do1 // 执行成功 UnLock1 // Lock2已经持有了内部锁localMtx，等待localMtx释放 routine 2 Lock2 // 因为routine1先获取到了redis锁，所以等待在Lock的itn.locker.lock()那行，持有了localMtx锁 func (itn *internal) Lock() { itn.localMtx.Lock() itn.locker.lock()...

(gherkin) Rule keyword is not highlighted

2

**Describe the issue** Rule keyword is not highlighted **Which language seems to have the issue?** gherkin **Are you using `highlight` or `highlightAuto`?** highlight **Sample Code to Reproduce** ```gherkin Feature: foo...

(gherkin) highlight wrongly for unclosed '<'

2

**Describe the issue** When there is a '', the line and following lines are highlighted wrongly **Which language seems to have the issue?** gherkin **Are you using `highlight` or `highlightAuto`?**...