theblacksquid
theblacksquid
Maybe it's because you called up the lambda expression without it operating on any parameters. I ran: `((lambda (a . b) 0) 'a)` It returned: `=> 0` BTW: Biwascheme currently...
(Disclosure: I don't know much about how Haskell does typing) Are there any benefits to Haskell type signatures/ML type declarations as opposed to type declarations inside the functions themselves in...
Absolutely, here's the [results]. [results]: https://gist.github.com/theblacksquid/eded5a0870ab24ba0b99c1366473113f
Just want to confirm that the build 2024-01-14-0248 also has this on linux.