Srikanth Reddy Lingala

You have to use the complete path in `getFileHeader()` method. In your case, for example, if you want to extract `A/B/C/word.text`, you have to use `zipFile.getFileHeader("A/B/C/word.text")`

Question answered [here](https://github.com/srikanth-lingala/zip4j/issues/459)

Hi, I don't have access to a Centos to try this out. I will try to setup a VM with Centos but that will take a while for me to...

> I have got a problem with zip4j above 2.0 version. BTW, to be precise, which version of zip4j are you using?

Strangely, on my mac I am able to extract your zip file with inbuilt zip utility, and also with the app called "The Unarchiver". But Keka, which uses 7zip in...

Hi. Thanks for your detailed analysis. I will have a look into the sample code and ACC, and post an update here.

@RinOrz Unfortunately there is no progress yet. I am extremely short on free time now a days, and I did not find time to work on this feature yet.

A similar question was answered [here](https://github.com/srikanth-lingala/zip4j/issues/427#issuecomment-1128282158)

Hi, I was a little busy the last days. I will look into this this week.

Canonical path check is needed to avoid a [zip slip exploit][1]. I cannot unfortunately remove this check. When you debug zip4j, what is the value of `outputCanonicalPath` and `outputFileCanonicalPath` on...