nitish28

Function continue to process even after host has stopped due to timeout, leaves item in the queue and results in duplicate processing of same message

2

Function sample code: for (var i = 0; i < 4; i++) { log.Info($"Next visible {i} : {myQueueItem}"); await Task.Delay(1000); } Host.json settings: { "queues": { "maxPollingInterval": 1000, "visibilityTimeout": "00:00:10",...