Hardik Joshi

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Hello @mvitale , following should work fine and it also avoids additional `with` clause. ``` User.as(:user).friends.query_as(:friend) .with(:user, :friend) .order('user.id', 'friend.name ASC') .return(:user, 'collect(friend)[0..5] AS top_friends_alphabetically') ``` It generates following cypher,...