Mehdi Gholam

Thanks but it will break existing use of `RegisterCustomType()`

Please post your json string.

Try : ``` ( JSON.Parse(sJson) as Dictionary) ["data"].Count // in c# ```

Can you provide an example of what you mean?

`JSON.Parse()` does not process the self referencing `$i` properties (which would require type information), so what you are asking does not work with your type of json data. The only...

Is the year, month, day...seconds the same?

If you add the following: ```c# Console.WriteLine(m.LogUtcTime); Console.WriteLine(gBack.LogUtcTime); ``` You will get : ``` 2021-12-26 15:42:12 2021-12-26 15:42:12 ``` Which shows the dates are the same, however the objects will...

My results ``` ***** tests.aaaaaaa Source:2021-12-29 06:15:41 JsonText: {"$types":{"tests+Model, UnitTests, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null":"1"},"$type":"1","ID":100,"UtcTime":"2021-12-29T06:15:41Z"} GetBack:2021-12-29 06:15:41 ```

Try testing @12:00 noon

also ```c# var jsonText = fastJSON.JSON.ToJSON(model, new JSONParameters { UseUTCDateTime =true}); var gBack = fastJSON.JSON.ToObject(jsonText , new JSONParameters { UseUTCDateTime=true}); ```