justin321123

Bypass

1

'def follow_accounts(bot_config): bot = Bot() bot.login(username=bot_config["username"], password=bot_config["password"])' I have this code, but instagram requests a security code due to suspecious login. Is it possible to make something in the script...

Same Issue is back.

9

` File "/home/container/.local/lib/python3.12/site-packages/discord/ext/commands/core.py", line 235, in wrapped ret = await coro(*args, **kwargs) ^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/home/container/bot.py", line 252, in chatgpt response = conversation.prompt(question) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ File "/home/container/.local/lib/python3.12/site-packages/ProGPT/Conversation.py", line 91, in prompt if...