Ilya Ovdin

i'd expect `(. (foo) (bar))` to be translated to `foo().bar()` which actually translates to `foo()[bar()]`

@vendethiel right, but for long chains which happens quite often it becomes not that readable `(. (foo) (bar) (baz))` i have to write `((. ((. (foo) "bar") "baz)))`

@vendethiel thanks