gitsirsha

@orbeckst - Doing _[ts.time for ts in u.trajectory]_ provides the timesteps as expected. The issue we observed is the default [MDAnalysis.analysis.msd](https://docs.mdanalysis.org/2.9.0/documentation_pages/analysis/msd.html#mean-squared-displacement-mdanalysis-analysis-msd) calculates the **_time-averaged MSDs_** as if the time were...