Polaris Feng
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2
issues of
Polaris Feng
背包加密中Archaic题目中的makeKey函数，原题中是 ```python def makeKey(n): privKey = [random.randint(1, 4**n)] s = privKey[0] for i in range(1, n): privKey.append(random.randint(s + 1, 4**(n + i))) s += privKey[i] q = random.randint(privKey[n-1] + 1,...
generate idle_dict at normalize using %idle of all cpus rather than the last cpu.