Sergey Kojoian

Results 2 comments of Sergey Kojoian

Hi Joe, Glad you are finding the resource useful. Regarding your question, P(A,B|C) is not equal P(A|B,C)P(B,C), but it is equal to P(A|B,C)P(B|C). Image the conditioning isn't there. You'd have...

Hi Omar, feel free to open a pull request.