Cleopatra Enjeck

It'll be nice to have an API, so that people can just specify a query string and use the URL as an image source.

- Like from 1 to 10 how complex the equation should be. Then you would have to add things like 2=(8-2)/6+1 for the easy ones and so on. - set...

The lazy way to do it would be to take what we have now and just divide by 1000 (or a random int between x and y), multiply by that...

Hopefully, this fixes the `Ambigous use of \over` error

Add these instructions to the README or a separate markdown document.