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Semi-automatic flattening of functions in a composition

Open egnha opened this issue 5 years ago • 0 comments

This affects indexing semantics. Currently, ((f) %>>>% g)[[1]] is always f, but (f %>>>% g)[[1]] is the first function in the flattened composite, which is not necessarily f (because f itself may be a composite function). This could be surprising.

egnha avatar Dec 09 '18 06:12 egnha