Ben

如果能加入声调就更好了

My solution is init a dictionary, when the targeted string is returned, you can use dictionary to give a value.

Did you check which headers that you include?

不建议升级到10.12太坑

第四题也是这么表述的，说的是结果。我的意思是，既然copy给出的是个immutable 对象，为何 ``` NSMutableString *mStringCopy = [string copy]; ``` 能够运行成功？

@wtuyp 我觉得应该是这样的 ``` NSMutableString *string = [NSMutableString stringWithString: @"origin"]; //copy NSString *stringCopy = [string copy]; NSMutableString *mStringCopy = [string copy]; // 能够完成赋值, 这个时候并不检查mStringCopy类型 NSMutableString *stringMCopy = [string mutableCopy]; //change value...

use `.setIsUseDetailView(false)`

Same problem.

This issue seems still exist in 2.6.1

@kamvoick I tried with the above method which is not working. For people who met this problem, using `JavaScript` is the only option.