Sean Phillips

bump, I haven't found clear leads. There have been some pointers to possibly modifying QEMU's startup, however I have been looking for a easier solution first before I get into...

Fairly old post, but the explanation is correct. Since c = -1, the if statement containing the break will not execute and it will fall through to the second for...

You're correct. After quickly testing it myself I believe there is an error in the description as @drymon mentioned.