Rock Liang
Rock Liang
Thanks. So like this? ```rust ... let result = a.qr(&b); ... ``` - but still doesn't work.
I figured, Yeah still didn't work ```rust let result = a.qr_square_inplace(&b); ```
- The problem is i am not sure which implementation is correct. - I am struggling to figure out a way make sure some trait implementations works by `use`
So what am i fixing next? @karimsa