Grapelllar

当cron表达式为 * * * * * ? * 时，报错

1

this is my code: > timers[quartzJob.dynamicQuartz[key].id] = later.setInterval( > async () => { await runQuartzJob(quartzJob.dynamicQuartz[key]); }, > later.parse.cron(quartzJob.dynamicQuartz[key].cron, true) > ); [2023-05-29T16:42:33.600] [DEBUG] [lib/module/quartz-server] what is parse cron * *...