liuduanhui

Yep. From my point of view, this operator can support half, float and double datatype if we change it to "dist2 = target.new_zeros(target.shape)". I think the problem is that the...

The 245~257, scan step will delete the point (-0.000094, 0.000155) according to its rule, so there will only 4 points left. after scanning: x,y: 0.000000, 0.000000 x,y: 0.002780, 0.000530 x,y:...

Yes. The points with small angles was ignored with a threshold(1e-6).(Your iou result is correct). So will you fix this error with a patch? Further more, this case can be...

OK, Thank you for your reply very much!!! I will wait for the patch. (ps: Will there is a patch for 1.6.1 or only for master?) (ps2: One more thing,...