where where

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But it works on my device. I need to know the difference to figure out what happened... And why you connect a connected device?

```cs var serial = client.GetDevices().FirstOrDefault().Serial; // You get the first connected device's serial. client.Connect(serial); // Then you connect it again. var deviceData = client.GetDevices().FirstOrDefault(); // Now I don't know which...

```cs var client = new AdbClient(); AdbServer.Instance.StartServer("adb/to/your/path", false); client.Connect("ip:port") var device = new DeviceClient(client, client.GetDevices().First()); device.StartApp("packagename"); ```

No, you can only use ip and port like `192.168.1.19:37146`. If you connected with USB, you can ignore it.

You can only use SyncService onetime. If it returns 0, you need to ReOpen it.

``` > igd10iumd64.dll!00007ffa88498e1e() 未知 igd10iumd64.dll!00007ffa884cf9f7() 未知 igd10iumd64.dll!00007ffa884cf1a0() 未知 igd10iumd64.dll!00007ffa884ce2d8() 未知 igd10iumd64.dll!00007ffa884cc51b() 未知 igd10iumd64.dll!00007ffa884cc35b() 未知 igd10iumd64.dll!00007ffa884c7d99() 未知 igd10iumd64.dll!00007ffa8846483e() 未知 igd10iumd64.dll!00007ffa883b1656() 未知 igd10iumd64.dll!00007ffa883b0ff6() 未知 igd10iumd64.dll!00007ffa882b3fbe() 未知 igd10iumd64.dll!00007ffa882b14a5() 未知 d3d11.dll!00007ffa92b8ec73() 未知 d3d11.dll!00007ffa92bc93f4() 未知...