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theory

Open jovo opened this issue 8 years ago • 0 comments

in biau08a, they point out in Fig 1, that certain greedily grown trees fail to converge here, but breiman's would converge.

can we think of an example where brieman would NOT be consistent. their proof suggests such distributions exist. we should think of one, and show that RerF converges even though RF does not (at least empirically)

jovo avatar Jan 18 '17 05:01 jovo