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A call to `sync()` freezes the app with unavailable sync URL

Open penberg opened this issue 2 years ago • 0 comments

The following just freezes the app so badly that even Ctrl-C doesn't work if there's nothing listening to the sync_url:

import libsql_experimental

con = libsql_experimental.connect("hello.db", sync_url="http://localhost:8080", auth_token="")

con.sync()

penberg avatar Nov 29 '23 10:11 penberg