if ! var=$(func) parser failure

[pschmitt]

Hi, the following code generated a parser failure (but is valid bash):

if ! x=$(false)
then
  :
fi

[TravonteD]

After investigating, it seems that the issue here is that the parser expects the condition to be terminated with a semicolon

if ! x=$(false);
then
  :
fi

parses correctly.

[Ordoviz]

Might be fixed by #183