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why “join_broadcast” is called twice?

Open videni opened this issue 10 months ago • 1 comments

it seems it is not necessary to call join_broadcast twice inside start_websocket_client_sync function.

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videni avatar Mar 12 '25 10:03 videni

i believe this is an error caused by a rebase of the code, this line can be removed

darkskygit avatar Mar 12 '25 14:03 darkskygit