every() depends on vector order when NA is present

[alberto-dellera]

library(purrr)

every( c(FALSE, NA), identity )
#> [1] FALSE
every( c(NA, FALSE), identity )
#> [1] NA

IMHO it should return the same and be consistent with &&:

FALSE && NA
#> [1] FALSE
NA && FALSE
#> [1] FALSE

[lionel-]

I think your analysis is correct. Especially since some() is implemented using || so it has the same behaviour as that operator. It would make a lot of sense for every() to behave like &&. This would be a behaviour change though :/

[hadley]

While this will change behaviour, I wouldn't characterise it as a breaking change; more that it's fixing a bug.