Ignoring an argument for typer command

[lvijnck]

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Example Code

def serialize_dfs(func):
    """Decorator function to automatically (de)-serialize input and output
    dataframes for the function. It leverages the `df_path` and `df_output_path`
    kwargs to serialize input and output dataframes respectively.

    Args:
        func: function to decorate
    Returns:
        List of deduplicated column names
    """
    def wrapper(
        *args,
        dataframe: Optional[pd.DataFrame] = None,
        df_path: Optional[str] = None,
        df_output_path: Optional[str] = None,
        **kwargs
    ):
        # When df path specified, load it and pass it into the function
        if df_path:
            dataframe = pd.read_csv(df_path)

        # Invoke original function
        result: pd.DataFrame = func(*args, dataframe=dataframe, **kwargs)

        # When output path specified, serialize it into output
        if df_output_path:
            result.to_csv(df_output_path, index=False)

        return result

    return wrapper

@app.command()
@serialize_dfs
def expand_columns(
    dataframe: pd.DataFrame = typer.Argument(lazy=True, default=None, formats=[""], hidden=True, expose_value=False),
    keys_col: str = "metadata_name",
    values_col: str = "metadata_value",
    col_format: str = "{column_name}{num}",
) -> pd.DataFrame:
   # ... logic here

Description

I have a few functions that I want to type that handle dataframes (both as input and output). I do have a decorator that allows for specifying the dataframes as paths (as opposed to the objects).

Out of this decorator, I now wish to construct a Typer command. Though I keep getting the following error:

RuntimeError: Type not yet supported.

Is there an option to completely ignore an argument to the Typer CLI? I tried:

• Hidden=True
• Default=None
• Expose_value=False
• Lazy=True

Operating System

macOS

Operating System Details

No response

Typer Version

typer==0.6.1

Python Version

3.9

Additional Context

No response