peeble
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fix: PhpCall (PhpVar) translating to 'name' instead of '$name'
I was getting outputs where the code was calling
$fn($arg1, $arg2)
instead of
fn($arg1, $arg2)
(which caused a problem because the variable $fn
doesn't exist)
Probably because this line is commented out https://github.com/thinkbeforecoding/peeble/blob/244c6f5ed87b9d96755b2fd44ea710c0dbcbd3db/src/peeble/Transforms.fs#L404