python-tidal
python-tidal copied to clipboard
tamland
403 Client Error: Forbidden for url: https://api.tidalhifi.com/v1/login/username
Not sure if it not the same problem as discribed here:
https://github.com/tamland/python-tidal/issues/65
But, then I try use simple example usage:
import tidalapi
session = tidalapi.Session()
session.login('[email protected]', 'mypassword')
tracks = session.get_album_tracks(album_id=16909093)
for track in tracks:
print(track.name)
I get this error:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<HTML><HEAD><META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1">
<TITLE>ERROR: The request could not be satisfied</TITLE>
</HEAD><BODY>
<H1>403 ERROR</H1>
<H2>The request could not be satisfied.</H2>
<HR noshade size="1px">
Request blocked.
We can't connect to the server for this app or website at this time. There might be too much traffic or a configuration error. Try again later, or contact the app or website owner.
<BR clear="all">
If you provide content to customers through CloudFront, you can find steps to troubleshoot and help prevent this error by reviewing the CloudFront documentation.
<BR clear="all">
<HR noshade size="1px">
<PRE>
Generated by cloudfront (CloudFront)
Request ID: sKUMth11MHMiKf0cWbBmNelWPrCh3HF8OpQWjnZqxmCK_MuhJ1JpjA==
</PRE>
<ADDRESS>
</ADDRESS>
</BODY></HTML>
Traceback (most recent call last):
File "\Python\test.py", line 4, in <module>
session.login('[email protected]', 'mypassword')
File "\Python\tidalapi\__init__.py", line 98, in login
request.raise_for_status()
File "\Python\lib\site-packages\requests\models.py", line 941, in raise_for_status
raise HTTPError(http_error_msg, response=self)
requests.exceptions.HTTPError: 403 Client Error: Forbidden for url: https://api.tidalhifi.com/v1/login/username
Is any solutions for this? Thanks!
Use new login method - oauth2. Legacy login method is being killed by tidal.
EDIT: It looks like bot detection was triggered on your request. That's bad. Anyway: try OAuth2.
Thanks for your answear! I understand correctly that new login method - oauth2 is not provided in this api, and I have to get the token in another way?
