interview_python
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交叉链表求焦点,修改了一下后面那个解答是错误的
遍历完长链表直接就返回了肯定不对啊
l1 = headA
l2 = headB
while l1 != l2:
l1 = l1.next if l1 else headB
l2 = l2.next if l2 else headA
return l1