swc-project
Function parameter's default value incorrectly captures other destructured parameter using spread operator
Describe the bug
Destructured variable is referenced as a default value before being declared
Input code
function foo({ a, ...rest }: {}, foo: unknown = rest): unknown {
}
Config
{
"jsc": {
"parser": {
"syntax": "typescript",
"tsx": false
},
"target": "es2015",
"loose": false,
"minify": {
"compress": false,
"mangle": false
}
},
"module": {
"type": "es6"
},
"minify": false,
"isModule": true
}
Playground link (or link to the minimal reproduction)
https://play.swc.rs/?version=1.6.7&code=H4sIAAAAAAAAA0srzUsuyczPU0jLz9eoVkjUUdDT0ytKLS5RqLVSqK7VAYlbKZTmZefll%2Bcp2CqApDQRAgrVXFy1ClwA73sdnEYAAAA%3D&config=H4sIAAAAAAAAA1VPSQ7CMAy85xWRzxwACQ78gUdEwa2Csil2JaKqfydpk0Jv9iye8SykhDdpeMi5jGWJKhGmfS8IZc%2FqUxDgHJF0MpHh1FmmSg3KEq7QsjHAKo3I1YV0PV9uzQE2BMLuaJgz3gz5P1MHFxMSHYVVqvxo8ZgoWiq48JpWsv1S%2B24N7vAT9bD9MBh6dienCcXyBbnuEC8XAQAA
SWC Info output
No response
Expected behavior
SWC should output code for parameter default value after the destructuring code
Actual behavior
Targeting ES2015 and below, transpiled code is incorrect as it references undeclared variable, pay attention to foo1 = rest:
function foo(_param, foo1 = rest) {
var { a } = _param, rest = _object_without_properties(_param, [
"a"
]);
}
For modern ES that supports object spreading output is correct:
function foo({ a, ...rest }, foo1 = rest) {}
Version
1.6.7
Additional context
No response
