Question on slope creation code

[llamapolitics]

Hi! I'm working through your text analytics code with my own data set (One focused on social reviews from multiple sites for a specific brand). But I keep getting an error when trying to create the slopes that you use to map out the trend in word usage.

This is the code:

slopes <- word_month_counts %>% nest(-word) %>% mutate(model = map(data, mod)) %>% unnest(map (model, tidy)) %>% filter(term == "year") %>% arrange(desc(estimate))

And this is the error I'm getting:

Error in map(model, tidy) : object 'model' not found In addition: Warning message: All elements of ... must be named. Did you want data = c(month, n, month_total, percent, year)?

Any idea on what may be going on? I could share more information if this isn't enough. Everything prior to this point has worked, although I've had to replace some minor terms such as column names

[GuoYunZheSE]

Hi! I'm working through your text analytics code with my own data set (One focused on social reviews from multiple sites for a specific brand). But I keep getting an error when trying to create the slopes that you use to map out the trend in word usage.

This is the code:

slopes <- word_month_counts %>% nest(-word) %>% mutate(model = map(data, mod)) %>% unnest(map (model, tidy)) %>% filter(term == "year") %>% arrange(desc(estimate))

And this is the error I'm getting:

Error in map(model, tidy) : object 'model' not found In addition: Warning message: All elements of ... must be named. Did you want data = c(month, n, month_total, percent, year)?

Any idea on what may be going on? I could share more information if this isn't enough. Everything prior to this point has worked, although I've had to replace some minor terms such as column names

I think the tidyr package api has changed a little since this was written - here's a modification to the "slopes" chunk that works:

slopes <- word_month_counts %>%
nest(data = -word) %>%
mutate(model = map(data, mod),
model = map(model,tidy)) %>%
unnest(model) %>%
filter(term == 'year') %>%
arrange(desc(estimate))