Removing extra available variables

[jkiviluo]

V_units_available is just V_units_invested_available plus existing capacity and is not necessary. Should be replaced with expression.

[clizbe]

We should keep an eye out for others like this.

[clizbe]

If I'm understanding it correctly, this constraint determines the value of units_available: constraint_units_available.jl

In that file, it says (simplified): units_available - units_invested_available <= number_of_units

But according to jkiviluo (Juha Kiviluoma) it should be an equality, and therefore can be replaced with an expression.

Which is correct? Or am I misunderstanding the model?

[manuelma]

Looking at the formulation, units_available will always be equal to units_on in the optimal solution.

We have units_on <= units_available in a constraint, but it always binds in the solution.

So we could remove units_available for performance (and keep only units_on). Will do that now.