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Differential filter on input

Open larrykvit opened this issue 2 months ago • 0 comments

I was looking at the schematic for this board and I saw a differential low pass filter on the inputs with resistor R3, R4, and capacitor C1.

From my calculation, the cut off frequency for this filter is f = 1/(2*pi * 2 * R * C) = 1/(2*pi * 2 * 100 * 0.1*10^-6) = 7957 hz

The sampling rate is 80 Hz on the ADC, so why is the cut off frequency so high? I would imagine you would want the cut off frequency to be less than nyquist so that you don't get any aliasing.

image

larrykvit avatar Apr 24 '24 16:04 larrykvit