AWS lambda error: OSError: [Errno 38] Function not implemented

[Jopepato]

Please answer these questions before submitting your issue. Thanks!

1. What version of Python are you using (python --version)? Python 3.8
2. What operating system and processor architecture are you using (python -c 'import platform; print(platform.platform())')? aws lambda
3. What are the component versions in the environment (pip list)? asn1crypto==0.24.0 azure-common==1.1.25 azure-core==1.3.0 azure-storage-blob==12.2.0 boto3==1.9.253 botocore==1.12.253 certifi==2019.11.28 cffi==1.14.0 chardet==3.0.4 cryptography==2.8 docutils==0.15.2 future==0.18.2 idna==2.9 ijson==2.6.1 isodate==0.6.0 jmespath==0.9.5 msrest==0.6.11 oauthlib==3.1.0 pycparser==2.20 pycryptodomex==3.9.7 PyJWT==1.7.1 pyOpenSSL==19.1.0 python-dateutil==2.8.1 pytz==2019.3 requests==2.23.0 requests-oauthlib==1.3.0 s3transfer==0.2.1 six==1.14.0 snowflake-connector-python==1.9.1 snowflake-sqlalchemy==1.2.2 SQLAlchemy==1.3.14 urllib3==1.25.8
4. What did you do? If possible, provide a recipe for reproducing the error. A complete runnable program is good.

Hello, I am using aws lambda to connect to the snowflake database. Everything was working fine until I retrieved quite a lot of rows from the database. It happened that I encounter that error. I then checked and saw that the aws lambda does not support multithreading for python, and the library on the back is using it, then I followed this post: https://community.snowflake.com/s/article/Python-connector-2-0-0-incompatible-with-AWS-Lambda

Changed the version of snowflake, created the layer on lambda and uploaded it again. But same error occured, I do not know how to fix it...

[keller00]

Version < 2.0.0 is suggested for a different reason. This is a duplicate of: https://github.com/snowflakedb/snowflake-connector-python/issues/287 Please follow that ticket!

[github-actions[bot]]

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