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@ operator with symbol as first argument

Open pfdietz opened this issue 5 years ago • 0 comments

The UPDATE operator is designed to take a symbol (naming a function) as the first argument. However, this fails because @ does not recognize a symbol as a function, but instead tries to call lookup on it.

(@ #'- 3) ==> -3 (@ '- 3) ==> should be -3, but signal an error

pfdietz avatar Dec 29 '19 17:12 pfdietz