sharkdp
Option to output colored file name only
Given "aaa/bbb/entry" return only "color + entry + color reset".
Use case:
I have "$HOME/downloads", which happens to be a link, and a lot of other files from different directories in a list and want to colorize them.
The only way to get correct colorization is to be in the right directory for each entry in the list, this means starting a process for each entry and is prohibitively expensive.
I can send the full path but then I'd have to parse the colored string.
An alternative would be to output the colored path and the colored entry on different lines.
@sharkdp
They are different.
issue 70
Add a user defined $root to every input entry
issue 78
output only the colored basename without the path
orthogonality
a list of files could be passed as arguments with --root $root to be added to the files and --name-only would only return the basename of the file colored according to the file present int $root (ie could exist and be executable in $root).
You can do this with bfs:
$ bfs -color -prune -printf '%f\n' path/to/file1 path/to/file2
file1
file2
@tavianator I would but
positive: bfs is faster than lscolors negative: bfs doesn't accepted files on stdin which is a show stopper for me
If you can \0-separate them instead of \n, then it does support -files0-from -. If not, there's always xargs :)
@tavianator
I didn't get that far in the man page.
I'll probably end up writing a wrapper called 'lscolors' around 'bfs' till I find the time to replace it, I just found out that I use lscolors in 25 different places in my code!