sklearn-pandas
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License clarification
I'm a little confused on what the license is supposed to be.
With version 2.1.0, MIT is listed as the license in setup.py but the license file states Zlib. Is the python package actually under MIT and the license file is wrong or is MIT incorrect and it should be Zlib? htt ps://pypi.org/project/sklearn-pandas/
I also noticed that sklearn-pandas states BSD-3-Claues on conda-forge. Is this correct? https://anaconda.org/conda-forge/sklearn-pandas
Could any of the maintainers please advise on this issue?