Andrew Zyabin

Just convert the Buffer to a string. All 😝

Make something that enforces a 256-character encoding on strings. (Like, a Latin1String.) Then convert the Buffer to a string with that rule enforced and you're done. 😝

I suggested a *new* type.

in "(Like, a Latin1String.)"

So we may go only the hard path: using rubber ducks to resolve the problem.

Currying: `a => b => a+b` => `f(a, b)` IIRC Memoise: should be easy to do.

@ConorOBrien-Foxx can I plz make another porpoisal with that? ;3 (I _will_ credit you)

@vihanb fixed

Source diving shows that `Number` has undefined behaviour for `a * b` where `b` is neither a `Number` nor `String`. [Source](https://github.com/cheddar-lang/Cheddar/blob/develop/src/interpreter/core/primitives/op/number.es6#L70). Y no define behavior? :sob:

'cuz there weren't enough tag events 😜