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Denormalize is in place

Open tumble-weed opened this issue 7 years ago • 0 comments

If you run your code with 0 multiplied with all the loss terms, you will still see the image gradually get smoother. in the Denormalize function because the tensor is not getting cloned, it is doing the multiplication by s and addition of mu in place.

tumble-weed avatar Jul 18 '18 03:07 tumble-weed