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Add `{UniqueRc, UniqueArc}::into_pin`

Open ibraheemdev opened this issue 4 months ago • 3 comments

Proposal

Problem statement

Safely constructing a Pin<Rc<T>> or Pin<Arc<T>> where T: !Unpin.

Motivating examples or use cases

Box::into_pin currently provides a safe way to create a heap-allocated self-referential object.

struct SelfReferential {
    data: [u8; 64],
    slice: NonNull<[u8]>,
    _pin: PhantomPinned,
}

impl SelfReferential {
    fn new() -> Pin<Box<Self>> {
        let res = SelfReferential {
            data: [0; 64],
            slice: NonNull::from(&[]),
            _pin: PhantomPinned,
        };

        let mut boxed = Box::new(res);
        boxed.slice = NonNull::from(&boxed.data);
        Box::into_pin(boxed)
    }
}

However, there is no way of doing the same for Rc or Arc, as their Pin-related APIs are restricted by the fact that they are not unique. UniqueRc and UniqueArc should provide a way around this.

Solution sketch

impl<T: ?Sized, A: Allocator> UniqueRc<T, A> {
    pub fn into_pin(value: Self) -> Pin<Rc<T>>
    where
        A: 'static;
}

impl<T: ?Sized, A: Allocator> UniqueArc<T, A> {
    pub fn into_pin(value: Self) -> Pin<Arc<T>>
    where
        A: 'static;
}

Alternatives

Arguably, the methods should be named into_rc_pin and into_arc_pin, to be consistent with into_rc and into_arc. However, it doesn't seem at all useful to want a Pin<UniqueRc<T>>, as there's no way to go from that to a Pin<Rc<T>> without deconstructing the Pin, and a UniqueRc on its own is no more useful than a Box.

Note that along with Box::into_pin, there is also an implementation of From<Box<T, A>> for Pin<Box<T, A>>, which serves the same purpose. I'm not sure whether this should be added for UniqueRc and UniqueArc as well.

Links and related work

What happens now?

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  • We think this problem seems worth solving, and the standard library might be the right place to solve it.
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Second, if there's a concrete solution:

  • We think this specific solution looks roughly right, approved, you or someone else should implement this. (Further review will still happen on the subsequent implementation PR.)
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ibraheemdev avatar Aug 21 '25 19:08 ibraheemdev

I don't think that's sound assuming you can convert Pin<UniqueArc<T>> to Pin<Arc<T>> (which seems entirely reasonable) because UniqueArc<T> lets you create Weak<T>, so you can break the pinning guarantee:

fn move_pinned(v: T, f: fn(Pin<Arc<T>>)) -> T {
    let unique_arc = UniqueArc::new(v);
    let weak = UniqueArc::downgrade(&unique_arc);
    let pinned_arc: Pin<Arc<T>> = UniqueArc::into_pin(unique_arc).into();
    f(pinned_arc.clone());
    let arc = weak.upgrade().unwrap();
    drop(pinned_arc);
    Arc::into_inner(arc).unwrap()
}

programmerjake avatar Aug 21 '25 21:08 programmerjake

@programmerjake the proposed API creates a Pin<Arc<T>> directly. You're correct though, it would have to panic if any weak references were created (or alternatively, the API could be fallible). Note having this API on UniqueArc means there are no potential race conditions (and no need for locking the weak count, for example).

ibraheemdev avatar Aug 21 '25 22:08 ibraheemdev

Maybe instead of panicking if any Weak exist, it could dissociate them (and make a new allocation) if any exist, like make_mut does (in which case it could maybe be called make_pinned or something), or fail like get_mut does (maybe called try_into_pin then).

Alternately, this could be an unsafe API with the precondition that any Weaks pointing to the same allocation treat the pointee as pinned. Maybe coupled with a unsafe fn downgrade_pinned(this: &Pin<(Unique)Arc<T>>) -> Weak<T> with the same precondition.

Or maybe we could have a separate PinWeak<T> type whose upgrade returns Option<Pin<Arc<T>>>, and is obtained from safe fn downgrade_pinned(this: &Pin<(Unique)Arc<T>>) -> PinWeak<T>. (Or maybe Pin could be generalized so that Pin<Weak<T>> is usable, maybe even just with Pin::new_unchecked/Pin::into_inner_unchecked).

zachs18 avatar Nov 13 '25 18:11 zachs18