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how can we explain GAN works without I(X,Z) term?

Open bojone opened this issue 6 years ago • 2 comments

compared with wgan-gp or wgan-div, your new GAN has an additional I(X,Z) term on generator loss. This term may prevent generator from mode collapse.

As we known, wgan-gp or wgan-div can be trained successfully without I(X,Z). But as your derivation in your paper, I(X,Z) is indispensable.

Therefore, how can we understand the success of wgan-gp or wgan-div under your framework ?

bojone avatar Jan 28 '19 08:01 bojone

In a word, I am really interested in your model but I want to make the whole derivation more naturally.

bojone avatar Jan 28 '19 08:01 bojone

I would not like for you to think about GANs (wgan-gp, wgan) in the first place. The objective of this paper is to not find a new GAN. It's to start from the theory of maximum-likelihood energy-based models and find a better way of learning / training energy-based models.

The connection to GANs is just an interesting coincidence.

ritheshkumar95 avatar Jan 28 '19 14:01 ritheshkumar95