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Tinyint type with MySQL

Open dtrillo opened this issue 6 years ago • 1 comments

Hi again. I have been working more with the class, and I have some problems when using tinyiny data type on MySQL, because the output the the value is 0, in the JSON is "".

The way to solve this issue is by adding the following line after 908: if varType(value) = 16 then valueType = "Decimal"

And it solve another issue!

dtrillo avatar Sep 14 '18 10:09 dtrillo

Hi,

Thanks again for your contributions and sorry for the long time waiting for a reply.

Just added support for TinyInt in the development branch: 692126a.

Would you be able to test if that works for you?

Best, Ricardo

rcdmk avatar Sep 30 '22 03:09 rcdmk