CornerNet
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why embedding.size() is [2,128]?
Hello,thanks for your contribution,but how to do the embedding? The formula you describe in the paper is Lpull = 1/ N( (etk −ek)2 +(ebk −ek)2),I want to know the etk.size(). I print the tag0.size() ,it is [2,128],this makes me confused ...... can you help me ?
batch_size=2