iteration before '\0'

[casuis]

Hi, I think you i++ one time more line 24. *on get_next_line.c

[pasqualerossi]

Hey, Thankyou for messaging, is this what you mean?

    }
    i++;
    i++;
    buffer[i] = '\0';
    return (buffer);

[casuis]

Hi, I mean

if ((!buffer[i - 1] && !rd) || rd == -1) { free(buffer); return (NULL); } buffer[i] = '\0';Sorry for my english Le mar. 8 févr. 2022 à 16:32, Pasquale Emilio Rossi < @.***> a écrit :

Hey, Thankyou for messaging, is this what you mean?

}
i++;
i++;
buffer[i] = '\0';

return (buffer);

}

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[pasqualerossi]

Ohh as in remove the i++ from the code.

Don’t worry about your English, it’s pretty good!