Sort based on number/length of children

[flyte]

Is it possible somehow to sort based on the number of lines taken up by children of a given key?

For example, this:

c: foo
b:
  x: foo
  z: bar
  y: baz
a:
  - foo: bar
  - bar: foo

would sort as:

c: foo
a:
  - bar: foo
  - foo: bar
b:
  x: foo
  y: baz
  z: bar

Although not shown here, it'd be helpful if this was supported recursively too.

The use case for this is to avoid putting small keys/values after large, extensively indented ones, like this:

apiVersion: batch/v1beta1
kind: CronJob
metadata:
  name: some-cron
  namespace: my-namespace
spec:
  concurrencyPolicy: Forbid
  failedJobsHistoryLimit: 1
  jobTemplate:
    metadata:
      creationTimestamp: null
    spec:
      backoffLimit: 3
      template:
        metadata:
          creationTimestamp: null
        spec:
          containers:
            - name: somecron
              image: some/image:1.2.3
              imagePullPolicy: IfNotPresent
              args:
                - echo
              command:
                - Foo
              env:
                - name: ENVIRONMENT
                  value: my_env
                - name: ALLOWED_HOST
                  value: some.host.com
              resources:
                limits:
                  cpu: 1
                  memory: 500M
                requests:
                  cpu: 1
                  memory: 500M
              terminationMessagePath: /dev/termination-log
              terminationMessagePolicy: File
          dnsPolicy: ClusterFirst
          imagePullSecrets:
            - name: mysecrets
          restartPolicy: OnFailure
          schedulerName: default-scheduler
          terminationGracePeriodSeconds: 30
  schedule: 10 * * * *  # These keys should be moved above the huge 'jobTemplate' tree
  successfulJobsHistoryLimit: 3
  suspend: false