specfile
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Create Specfile from a virtual file
Currently, it is possible to create an object of Specfile
like this:
# using an absolute path
specfile = Specfile('/tmp/test.spec')
# using a relative path and a different sourcedir
specfile = Specfile('test.spec', sourcedir='/tmp/sources')
It would be nice to be able to create it also like this
with open('/tmp/test.spec', 'r') as fp:
specfile = Specfile(fp)
This alone is not so interesting, but it allows for creating Specfile
from a virtual file
from io import StringIO
fp = StringIO()
fp.write("Name: foo\nVersion: 1.0\nRelease: 1\n...")
specfile = Specfile(fp)
Of course, I am interested in the feature, not the exact syntax. My suggestion will probably have an issue with the .save()
method so if it is done like
specfile = Specfile(fp=fp)
# or
specfile = Specfile.from_fp(fp)
It is all fine with me :-)