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一行搞定,注意要先判断S是否完整包含T,使用includes即可 ```js ```javascript function findStr(S, T){ return S.includes(T) ? S.indexOf(T) : -1 } ``` 测试 ```js const S1 = 'abcdefg', T1 = 'cde', T2 = 'fgh' console.log(findStr(S1, T1)) // 2...

单纯从题意触发,add调用时候必须有toString之类的触发条件;用外部变量保存每次执行累计的参数列表,执行完toString之后清空即可: ```javascript // * 柯理化函数 let concatArgs = [] function add(...args) { concatArgs = concatArgs.concat(args) return add } add.toString = function () { const res = concatArgs.reduce((pre, cur) => pre...

please view on there:https://orime.gitee.io/brilliant-js/