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OpenMMLab FewShot Learning Toolbox and Benchmark

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Hi is there plans to update this repository to be compatible with MMEngine?

We meet problem when training on classification models. We test several times, the code is blocked on this line of command in classification.api.train

When I was studying the process of small sample learning, I came across tiff images in the data set. At this point, there is a problem with the dataset loading,...

**Describe the bug** I run the "demo/demo_attention_rpn_detector_inference.py.py" as example arguments, and it works. However, when I change the option "proto-net" to "baseline++" the error happened as follow. ``` File "C:\GitSource\SolVision3.0\AI_Vision_WPF\TaskProcess\bin\x64\Release\PYD\slmmm\packages\mmfewshot\demo\demo_metric_classifier_1shot_inference.py",...

I set evaluation = dict(interval=2000, metric='bbox', classwise=True, save_best='auto') to save the best weight like mmdetection, but it does not work. What should I do? thanks

In base training of Meta RCNN, when I use one_support_shot_per_iamge=True, the loss is normal,while when I use one_support_shot_per_iamge=False, the loss will become nan. besides, I find that only one target...

python ./tools/classification/train.py configs/classification/baseline/cub/baseline_conv4_1xb64_cub_5way-1shot.py No CUDA runtime is found, using CUDA_HOME=':/usr/local/cuda-11.1' Traceback (most recent call last): File "./tools/classification/train.py", line 13, in from mmcls.models import build_classifier File "/anaconda3/envs/openmmlab/lib/python3.7/site-packages/mmcls/models/__init__.py", line 2, in from...

How to set seed to non for training, so that the results have randomness

I am using a custom COCO-type dataset. The classes and everything are updated, and in my log file, it can pick up my dataset and divide it according to the...

I am using TFA, the dataset is in VOC format. I have total 5 classes and in three splits I am dividing it like this ALL CLASSES=[A,B,C,D,E] Split_1_base=[A,B,C,D] Split_2_base=[A,B,C] Split_3_base=[A,B]...