Filter for output of specific commands
Description: Allow me to filter which command outputs I want to display. Still run all tasks.
Use case: I want to debug a particular task of the set of tasks I run with concurrently and focus on its outputs. At the moment, I solve this by calling npm run dev | grep name-of-task. This works but potentially includes false positives. Additionally, concurrently will not color the task name because it is not directly attached to the terminal.
How does the existing --hide flag work for you?
I have a similar situation. I have two processes and would like to use --hide 1 --raw, so that only the output from the first process is displayed. Unfortunately, --raw seems to ignore any --hide argument.
Would it make sense to support this?
Yes, but note that raw mode implies inheriting stdio, which means no control over the output.
https://github.com/open-cli-tools/concurrently/blob/a61ef39468c82b66ebb247a5a5e2cf479a0c4def/src/get-spawn-opts.ts#L42
It might be possible to change it to ignore instead of inherit to support your use case.
How does the existing
--hideflag work for you?
It works I guess but I run many tasks, so it's much easier to list the task I want to see instead of every other task.
Thumbs up for --hide 1 --raw . Did anyone manage to get this working (with colors)?
Update: Found a surprisingly simple solution:
concurrently \"command-1\" \"command-2 > /dev/null 2>&1\" --raw
Hey @wottpal and @amannn, the --hide + --raw flag combo has been fixed by #486. It's not yet released.
☝️ It's been released now. https://github.com/open-cli-tools/concurrently/releases/tag/v9.0.0