需求：NutMap 对于json可变的结果集，可通过getAs强制得到List集合

[Wizzercn]

{
  "key":{
	"a":"aaaa0";
        "b":"bbbb0";
  }
}

{
  "key":{
	"a":"aaaa1";
        "b":"bbbb1";
  },
  "key":{
	"a":"aaaa2";
        "b":"bbbb2";
  }
}

NutMap json = Json.fromJson(NutMap.class, txt);

json.getAs("key",List.class);

[wendal]

{
  "key":[
       {
	  "a":"aaaa1",
          "b":"bbbb1",
      },
     {
	   "a":"aaaa2",
           "b":"bbbb2",
     }]
}

[Wizzercn]

@wendal 亲，数据接口是电信的，我改不了人家的接口啊，它就是这样BT的啊

[wendal]

JSON里面带重复key???

[Wizzercn]

@wendal 准确的说是xml：

<root>
	<web:NEW_DATA_TICKET_QRsp>
		<number>1064901037***</number>
		<TOTAL_BYTES_CNT>33.97MB</TOTAL_BYTES_CNT>
		<DURATION_CNT_CH>479小时53分钟45秒</DURATION_CNT_CH>
		<CHARGE_CNT_CH>0(元)</CHARGE_CNT_CH>
		<NEW_DATA_TICKET_QRlist>
			<TICKET_NUMBER>1</TICKET_NUMBER>
			<TICKET_TYPE>江苏南京</TICKET_TYPE>
			<SERVICE_TYPE>3G(EVDO)</SERVICE_TYPE>
			<START_TIME>2014-10-01 03:43</START_TIME>
			<DURATION_CH>6小时2秒</DURATION_CH>
			<TICKET_CHARGE_CH>0.00</TICKET_CHARGE_CH>
			<BYTES_CNT>267KB</BYTES_CNT>
			<CCG_PRODUCT_NAME />
		</NEW_DATA_TICKET_QRlist>
		<NEW_DATA_TICKET_QRlist>
			<TICKET_NUMBER>2</TICKET_NUMBER>
			<TICKET_TYPE>江苏南京</TICKET_TYPE>
			<SERVICE_TYPE>3G(EVDO)</SERVICE_TYPE>
			<START_TIME>2014-10-01 09:43</START_TIME>
			<DURATION_CH>6小时</DURATION_CH>
			<TICKET_CHARGE_CH>0.00</TICKET_CHARGE_CH>
			<BYTES_CNT>290KB</BYTES_CNT>
			<CCG_PRODUCT_NAME />
		</NEW_DATA_TICKET_QRlist>
		<NEW_DATA_TICKET_QRlist>
			<TICKET_NUMBER>3</TICKET_NUMBER>
			<TICKET_TYPE>江苏南京</TICKET_TYPE>
			<SERVICE_TYPE>3G(EVDO)</SERVICE_TYPE>
			<START_TIME>2014-10-01 15:43</START_TIME>
			<DURATION_CH>6小时</DURATION_CH>
			<TICKET_CHARGE_CH>0.00</TICKET_CHARGE_CH>
			<BYTES_CNT>296KB</BYTES_CNT>
			<CCG_PRODUCT_NAME />
		</NEW_DATA_TICKET_QRlist>
		<IRESULT>0</IRESULT>
		<SMSG>成功</SMSG>
	</web:NEW_DATA_TICKET_QRsp>
</root>

[Kerbores]

xpath

[wendal]

NutMap.getList会自动封装的

[Wizzercn]

问题是，有一个结果的时候封装成了对象，多个的时候变成list，我是想不管一个或多个都是list

[wendal]

哦,这是个问题

[wendal]

问题又来了, nutz如何知道某个属性是否应该是list呢...

Lang.map2obj的里面做些判断??

[Wizzercn]

List<NutMap> cumulRspList = new ArrayList<>();
                        Object v = web.get("CumulRspList");
                        if (v instanceof Collection) {
                            cumulRspList = web.getList("CumulRspList", NutMap.class);
                        }
                        if (v instanceof NutMap) {
                            cumulRspList.add((NutMap) v);
                        }

暂时是这样解决的