Eliminate repeated address shift calculations.

[nushio3]

These kind of repeated terms may be eliminated anyway by common subexpression eliminator, but is ugly, so let us unify them manually.

const int a5_0_0 = a1[((((i) % size0()) + 1 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + 1 + size1())%size1()))];
const int a7_0_0 = a1[((((i) % size0()) + 0 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + 1 + size1())%size1()))];
const int a9_0_0 = a1[((((i) % size0()) + -1 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + 1 + size1())%size1()))];
const int a11_0_0 = a1[((((i) % size0()) + 1 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + 0 + size1())%size1()))];
const int a13_0_0 = a1[((((i) % size0()) + -1 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + 0 + size1())%size1()))];
const int a15_0_0 = a1[((((i) % size0()) + 1 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + -1 + size1())%size1()))];
const int a17_0_0 = a1[((((i) % size0()) + 0 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + -1 + size1())%size1()))];
const int a19_0_0 = a1[((((i) % size0()) + -1 + size0())%size0()) + size0() * (((((i / size0()) % size1()) + -1 + size1())%size1()))];